L1VM - course 02
L1VM - course 02
switch
In the first part of the course you did learn how to write a simple “Hello world!” program.
And what the “if” and “if+” statement can do.
But what if you have to do multiple checks if a variable has some value and do something? In this case you can use the “switch” statement:
(switch)
(y 23_const ?)
print_s (23_str)
print_n
(break)
(y 42_const ?)
print_s (42_str)
print_n
(break)
(switchend)
The “?” stands for branch if equal. So if “y” is of value “23_const” the string “23_str” is printed.
Note: the “(break)” statement does not “break” the “switch” statement. It Is just like an “endif”.
So if the first switch statement is true then it continues with the “(y 42_const ?)” comparison.
And there is no “default” statement like in C or C++ for example!
Here is a full example:
// switch.l1com
// Brackets - Hello world! switch
//
#include <intr.l1h>
(main func)
(set int64 1 zero 0)
(set int64 1 x 23)
(set int64 1 y 42)
(set string s 23_str "y = 23")
(set string s 42_str "y = 42")
(set const-int64 1 23_const 23)
(set const-int64 1 42_const 42)
(set string s hello_str "Hello world!")
(set int64 1 a 0)
// print string
print_s (hello_str)
print_n
((x y *) a =)
print_i (a)
print_n
(switch)
(y 23_const ?)
print_s (23_str)
print_n
(break)
(y 42_const ?)
print_s (42_str)
print_n
(break)
(switchend)
exit (zero)
(funcend)
Here is the output:
$ l1vm prog/switch -q
Hello world!
966
y = 42
In this program “intr.l1h” includes the macros for the interrupt functions. So you can use “print_i” and “print_s” for example instead of the interrupt statement with the number codes.